Exercise
\sqrt{5^{2+\frac{1}{2}\log_5 16}}=
Final Answer
Solution
Using Logarithm Rules we get:
\sqrt{5^{2+\frac{1}{2}\log_5 16}}=
=\sqrt{5^2\cdot 5^{\frac{1}{2}\log_5 16}}=
=\sqrt{5^2\cdot 5^{\log_5 16^{\frac{1}{2}}}}=
=\sqrt{25\cdot 5^{\log_5 4}}=
=\sqrt{25\cdot 4}=
=\sqrt{100}=10