Continuity by Definition – Continuity check by definition to a function with parameters – Exercise 898 Post category:Continuity by Definition Post comments:0 Comments Exercise Given the function (a,b and c parameters) f(x)={x3+ax2+bx+c(x+1)2,x≠−1−3,x=−1f(x) = \begin{cases} \frac{x^3+ax^2+bx+c}{{(x+1)}^2}, &\quad x \neq -1\\ -3, &\quad x = -1\\ \end{cases}f(x)={(x+1)2x3+ax2+bx+c,−3,x=−1x=−1 For which values of the parameters is the function continuous? Final Answer Show final answer a=0,b=−3,c=−2a=0, b=-3, c=-2a=0,b=−3,c=−2 Solution Coming soon… Share with Friends Read more articles Previous PostContinuity by Definition – Continuity check by definition to a function with parameters – Exercise 920 Next PostContinuity by Definition – Continuity check by definition to a function with a parameter – Exercise 891 You Might Also Like Proof of Continuity – A split function with a polynomial and a rational function – Exercise 5871 June 30, 2019 Proof of Continuity – A split function with exponential and rational functions – Exercise 6245 July 5, 2019 Proof of Continuity – A split function with an exponential function and a parameter – Exercise 6257 July 5, 2019 Proof of Continuity – A split function with polynomials – Exercise 6243 July 5, 2019 Proof of Continuity – A split function with A quotient of functions with a square root and a parameter – Exercise 6250 July 5, 2019 Proof of Continuity – A split function with a function to the power of a function – Exercise 6236 July 5, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
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