Continuity by Definition – Continuity check by definition to a function with a parameter – Exercise 884 Post category:Continuity by Definition Post comments:0 Comments Exercise Given the function (c parameter) f(x)={ex2−13x2,x≠0c,x=0f(x) = \begin{cases} \frac{e^{x^2}-1}{3x^2}, &\quad x\neq 0 \\ c, &\quad x =0\\ \end{cases}f(x)={3x2ex2−1,c,x=0x=0 For which values of the parameter is the function continuous? Final Answer Show final answer c=13c=\frac{1}{3}c=31 Solution Coming soon… Share with Friends Read more articles Previous PostContinuity by Definition – Continuity check by definition to a function with a parameter – Exercise 891 Next PostContinuity by Definition – Continuity check by definition to a function with parameters – Exercise 859 You Might Also Like Proof of Continuity – A split function with rational functions and parameters – Exercise 6594 July 16, 2019 Proof of Continuity – A split function with exponential functions – Exercise 6230 July 5, 2019 Proof of Continuity – A split function with a polynomial and a rational function – Exercise 5871 June 30, 2019 Proof of Continuity – A split function with an exponential function and a parameter – Exercise 6257 July 5, 2019 Proof of Continuity – A split function with polynomials – Exercise 6243 July 5, 2019 Proof of Continuity – A split function with exponential and rational functions – Exercise 6245 July 5, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
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