Continuity by Definition – Continuity check by definition to a function with parameters – Exercise 859 Post category:Continuity by Definition Post comments:0 Comments Exercise Given the function (a and b parameters) f(x)={x2+ax+bx−1,x≠14,x=1f(x) = \begin{cases} \frac{x^2+ax+b}{x-1}, &\quad x \neq 1\\ 4, &\quad x = 1\\ \end{cases}f(x)={x−1x2+ax+b,4,x=1x=1 For which values of the parameters is the function continuous? Final Answer Show final answer a=2,b=−3a=2, b=-3a=2,b=−3 Solution Coming soon… Share with Friends Read more articles Previous PostContinuity by Definition – Continuity check by definition to a function with a parameter – Exercise 884 Next PostContinuity by Definition – Classify type of discontinuity – Exercise 831 You Might Also Like Proof of Continuity – A split function with exponential and rational functions – Exercise 6245 July 5, 2019 Proof of Continuity – A split function with first degree polynomial functions – Exercise 6220 July 5, 2019 Proof of Continuity – A split function with a function to the power of a function – Exercise 6236 July 5, 2019 Proof of Continuity – A split function with polynomial functions and a parameter – Exercise 5876 June 30, 2019 Proof of Continuity – A split function with a rational function and a parameter – Exercise 6252 July 5, 2019 Proof of Continuity – A split function with exponential functions and a parameter – Exercise 6591 July 16, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
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