Continuity by Definition – Continuity check by definition – Exercise 825 Post category:Continuity by Definition Post comments:0 Comments Exercise Given the function f(x)={e3x,x<0x2,x≥0f(x) = \begin{cases} e^{3x}, &\quad x<0\\ x^2, &\quad x \geq 0\\ \end{cases}f(x)={e3x,x2,x<0x≥0 Is it continuous? Final Answer Show final answer No. The point x=0x=0x=0 is a jump discontinuity point. Solution Coming soon… Share with Friends Read more articles Previous PostContinuity by Definition – Classify type of discontinuity – Exercise 831 Next PostContinuity by Definition – Continuity check by definition – Exercise 820 You Might Also Like Proof of Continuity – A split function with polynomials – Exercise 6243 July 5, 2019 Proof of Continuity – A split function with a quotient of functions and parameters – Exercise 5867 June 30, 2019 Proof of Continuity – A split function with polynomial functions and a parameter – Exercise 5874 June 30, 2019 Proof of Continuity – A split function with a rational function and a parameter – Exercise 6252 July 5, 2019 Proof of Continuity – A split function with polynomial functions and a parameter – Exercise 5876 June 30, 2019 Proof of Continuity – A split function with rational functions and parameters – Exercise 6594 July 16, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Proof of Continuity – A split function with a quotient of functions and parameters – Exercise 5867 June 30, 2019
Proof of Continuity – A split function with polynomial functions and a parameter – Exercise 5874 June 30, 2019
Proof of Continuity – A split function with a rational function and a parameter – Exercise 6252 July 5, 2019
Proof of Continuity – A split function with polynomial functions and a parameter – Exercise 5876 June 30, 2019
Proof of Continuity – A split function with rational functions and parameters – Exercise 6594 July 16, 2019
