Extremum, Increase and Decrease sections – Extremum to an exponential function in a closed interval – Exercise 6911 Post category:Extremum, Increase and Decrease Sections Post comments:0 Comments Exercise Determine the absolute extrema for the following function f(x)=2xf(x)=2^xf(x)=2x On the closed interval [−1,5][-1,5][−1,5] Final Answer Show final answer max[−1,5]f(x)=32\max_{[-1,5]}f(x)=32[−1,5]maxf(x)=32 min[−1,5]f(x)=12\min_{[-1,5]}f(x)=\frac{1}{2}[−1,5]minf(x)=21 Solution Coming soon… Share with Friends Read more articles Previous PostExtremum, Increase and Decrease sections – Min/Max problems (maximal volume) – Exercise 6897 Next PostExtremum, Increase and Decrease sections – Extremum to a polynomial function in a closed interval – Exercise 6913 You Might Also Like Extremum, Increase and Decrease sections – Extremum to a polynomial function in an absolute value in a closed interval – Exercise 6918 July 30, 2019 Extremum, Increase and Decrease sections – Extremum to a function with a third root in a closed interval – Exercise 6878 July 28, 2019 Extremum, Increase and Decrease Sections – A polynomial – Exercise 6826 July 25, 2019 Extremum, Increase and Decrease Sections – A rational function – Exercise 6820 July 24, 2019 Extremum, Increase and Decrease sections – Extremum to a polynomial function in a closed interval – Exercise 6876 July 28, 2019 Extremum, Increase and Decrease sections – Min/Max problems (maximal volume) – Exercise 6897 July 29, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
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