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Extremum, Increase and Decrease sections – Extremum to a function with a third root in a closed interval – Exercise 6878

Determine the absolute extrema for the following function

$f(x)=x^2\sqrt[3]{6x-7}$

On the closed interval

$[-1,2]$

Final Answer

$\max_{[-1,2]}f(x)=f(2)=6.84$

$\min_{[-1,2]}f(x)=f(-1)=-2.35$

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