Extremum, Increase and Decrease sections – Extremum to a polynomial function in a closed interval – Exercise 6876

Exercise

Determine the absolute extrema for the following function

f(x)=3x4+4x312x2f(x)=3x^4+4x^3-12x^2

On the closed interval

[3,2][-3,2]

Final Answer

max[3,2]f(x)=f(2)=32\max_{[-3,2]}f(x)=f(2)=32

min[3,2]f(x)=f(2)=32\min_{[-3,2]}f(x)=f(-2)=-32

Solution

Coming soon…

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