Improper Integral – A rational function on an infinite interval – Exercise 6612 Post category:Improper Integral Post comments:0 Comments Exercise Evaluate the integral ∫2∞1x2(x2−1)dx\int_{2}^{\infty} \frac{1}{x^2(x^2-1)} dx∫2∞x2(x2−1)1dx Final Answer Show final answer ∫2∞1x2(x2−1)dx=−12+12ln3\int_{2}^{\infty} \frac{1}{x^2(x^2-1)} dx=-\frac{1}{2}+\frac{1}{2}\ln 3∫2∞x2(x2−1)1dx=−21+21ln3 Solution Coming soon… Share with Friends Read more articles Previous PostImproper Integral – A multiplication of a polynomial and exponential functions on an infinite interval – Exercise 5406 Next PostImproper Integral – A rational function on an infinite interval – Exercise 6943 You Might Also Like Improper Integral – A multiplication of functions on an infinite interval – Exercise 6976 August 12, 2019 Improper Integral – A multiplication of a polynomial and exponential functions on an infinite interval – Exercise 5406 May 17, 2019 Improper Integral – A rational function on an infinite interval – Exercise 6974 August 12, 2019 Improper Integral – A functions multiplication with roots on an infinite interval – Exercise 6991 August 21, 2019 Improper Integral – A rational function on an infinite interval – Exercise 6952 August 12, 2019 Improper Integral – A rational function on an infinite interval – Exercise 6954 August 12, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Improper Integral – A multiplication of functions on an infinite interval – Exercise 6976 August 12, 2019
Improper Integral – A multiplication of a polynomial and exponential functions on an infinite interval – Exercise 5406 May 17, 2019
Improper Integral – A functions multiplication with roots on an infinite interval – Exercise 6991 August 21, 2019
