Global Extremum – Domain of a circle – Exercise 6538

Exercise

Find the maximum value and the minimum value of the function

z(x,y)=x2+y2z(x,y)=x^2+y^2

In the domain:

D={(x,y):x22x+y24y=0}D=\{ (x,y):x^2-2x+y^2-4y=0\}

Final Answer

maxDz(2,4)=20\max_D z(2,4) = 20

minDz(0,0)=0\min_D z(0,0) =0

Solution

Coming soon…

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