Global Extremum – Domain of a circle – Exercise 6538 Post category:Global Extremum Post comments:0 Comments Exercise Find the maximum value and the minimum value of the function z(x,y)=x2+y2z(x,y)=x^2+y^2z(x,y)=x2+y2 In the domain: D={(x,y):x2−2x+y2−4y=0}D=\{ (x,y):x^2-2x+y^2-4y=0\}D={(x,y):x2−2x+y2−4y=0} Final Answer Show final answer maxDz(2,4)=20\max_D z(2,4) = 20Dmaxz(2,4)=20 minDz(0,0)=0\min_D z(0,0) =0Dminz(0,0)=0 Solution Coming soon… Share with Friends Read more articles Previous PostGlobal Extremum – Domain of lines – Exercise 5529 Next PostGlobal Extremum – Domain of a circle – Exercise 6543 You Might Also Like Global Extremum – Domain of ellipse – Exercise 4749 May 6, 2019 Global Extremum – Domain of ellipse – Exercise 5392 May 15, 2019 Global Extremum – Domain of a circle – Exercise 6543 July 15, 2019 Global Extremum – Domain of lines – Exercise 5529 June 9, 2019 Global Extremum – Domain of a function with fixed negative powers – Exercise 6551 July 23, 2019 Global Extremum – Domain of lines – Exercise 3443 February 21, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
