Definite Integral – Split function on finite interval – Exercise 6444 Post category:Definite Integral Post comments:0 Comments Exercise Given f(x)={−1,0≤x≤12x−3,1<x<20,x≥2,x<0f(x) = \begin{cases}-1, &\quad 0\leq x\leq 1\\ 2x-3, &\quad 1<x<2\\ 0, &\quad x\geq 2, x<0\\ \end{cases}f(x)=⎩⎪⎪⎨⎪⎪⎧−1,2x−3,0,0≤x≤11<x<2x≥2,x<0 Evaluate the integral ∫−14f(x)dx\int_{-1}^4 f(x) dx∫−14f(x)dx Final Answer Show final answer ∫−14f(x)dx=−1\int_{-1}^4 f(x) dx=-1∫−14f(x)dx=−1 Solution Coming soon… Share with Friends Read more articles Previous PostDefinite Integral – rational function in absolute value inside ln function on symmetric interval – Exercise 6442 Next PostDefinite Integral – Split function on finite interval – Exercise 6448 You Might Also Like Definite Integral – A rational function on a symmetric interval – Exercise 6423 July 8, 2019 Definite Integral – A quotient of functions with absolute value on a symmetric interval – Exercise 6431 July 8, 2019 Definite Integral – An exponential function on a finite interval – Exercise 6421 July 8, 2019 Definite Integral – Finding area between two curves – Exercise 6615 July 16, 2019 Definite Integral – Finding area between two functions and an asymptote – Exercise 5492 May 25, 2019 Definite Integral – A polynomial on a symmetric interval – Exercise 6409 July 8, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Definite Integral – A quotient of functions with absolute value on a symmetric interval – Exercise 6431 July 8, 2019
