Definite Integral – A polynomial in absolute value on a finite interval – Exercise 6436 Post category:Definite Integral Post comments:0 Comments Exercise Evaluate the integral ∫−13∣2x−2∣dx\int_{-1}^3 |2x-2| dx∫−13∣2x−2∣dx Final Answer Show final answer ∫−13∣2x−2∣dx=8\int_{-1}^3 |2x-2| dx=8∫−13∣2x−2∣dx=8 Solution Coming soon… Share with Friends Read more articles Previous PostDefinite Integral – x in absolute value on a finite interval – Exercise 6434 Next PostDefinite Integral – A quotient of exponential functions on a symmetric interval – Exercise 6439 You Might Also Like Definite Integral – Finding area between two curves – Exercise 6615 July 16, 2019 Definite Integral – A rational function on a finite interval – Exercise 6403 July 8, 2019 Definite Integral – Finding area between a polynomial and asymptotes – Exercise 6783 July 23, 2019 Definite Integral – An exponential function on a finite interval – Exercise 6421 July 8, 2019 Definite Integral – Finding area between 2 polynomials – Exercise 7009 August 21, 2019 Definite integral – area computation of a bounded domain – Exercise 6615 July 20, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
