Definite Integral – A rational function on a symmetric interval – Exercise 6423 Post category:Definite Integral Post comments:0 Comments Exercise Evaluate the integral \int_{-1}^1 \frac{1}{2x+3} dx Final Answer Show final answer \int_{-1}^1 \frac{1}{2x+3} dx=\frac{1}{2}\ln 5 Solution Coming soon… Share with Friends Read more articles Previous PostDefinite Integral – An exponential function on a finite interval – Exercise 6421 Next PostDefinite Integral – A quotient of functions with a root on a finite interval – Exercise 6415 You Might Also Like Definite Integral – Finding area between a polynomial and a line – Exercise 6793 July 23, 2019 Definite Integral – Finding area between 3 functions – Exercise 5371 May 15, 2019 Definite Integral – Finding area between a polynomial and a line – Exercise 7002 August 21, 2019 Definite Integral – Finding area between a polynomial and asymptotes – Exercise 6783 July 23, 2019 Definite Integral – A quotient of functions with a root on a finite interval – Exercise 6415 July 8, 2019 Definite Integral – Finding area between two curves – Exercise 6615 July 16, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Definite Integral – A quotient of functions with a root on a finite interval – Exercise 6415 July 8, 2019