Definite Integral – A polynomial on a symmetric interval – Exercise 6409 Post category:Definite Integral Post comments:0 Comments Exercise Evaluate the integral ∫−11(3x+1)2dx\int_{-1}^1 {(3x+1)}^2 dx∫−11(3x+1)2dx Final Answer Show final answer ∫−11(3x+1)2dx=8\int_{-1}^1 {(3x+1)}^2 dx=8∫−11(3x+1)2dx=8 Solution Coming soon… Share with Friends Read more articles Previous PostDefinite Integral – A rational function on a finite interval – Exercise 6403 Next PostDefinite Integral – A quotient of functions on a finite interval – Exercise 6412 You Might Also Like Definite Integral – A rational function with absolute value on symmetric interval – Exercise 6601 July 16, 2019 Definite Integral – A rational function on a symmetric interval – Exercise 6423 July 8, 2019 Definite Integral – Split function on finite interval – Exercise 6444 July 9, 2019 Definite integral – area computation of a bounded domain – Exercise 6615 July 20, 2019 Definite Integral – A quotient of functions on a finite interval – Exercise 6412 July 8, 2019 Definite Integral – Finding area between a polynomial and a line – Exercise 7006 August 21, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Definite Integral – A rational function with absolute value on symmetric interval – Exercise 6601 July 16, 2019
