Proof of Continuity – A split function with A quotient of functions with a square root and a parameter – Exercise 6250 Post category:Continuity by Definition Post comments:0 Comments Exercise Given the function f(x)={x2+11−6x2−25,5≠x>0c,x=5f(x) = \begin{cases} \frac{\sqrt{x^2+11}-6}{x^2-25}, &\quad 5\neq x>0\\ c, &\quad x=5 \\ \end{cases}f(x)={x2−25x2+11−6,c,5=x>0x=5 c parameter. For what value of c is the function continuous at point x = 5? Final Answer Show final answer c=112c=\frac{1}{12}c=121 Solution Coming soon… Share with Friends Read more articles Previous PostProof of Continuity – A split function with exponential functions – Exercise 6230 Next PostProof of Continuity – A split function with a rational function and a parameter – Exercise 6252 You Might Also Like Proof of Continuity – A split function with a polynomial and a rational function – Exercise 5871 June 30, 2019 Proof of Continuity – A split function with polynomial functions and a parameter – Exercise 5876 June 30, 2019 Proof of Continuity – A split function with first degree polynomial functions – Exercise 6220 July 5, 2019 Proof of Continuity – A split function with polynomials – Exercise 6243 July 5, 2019 Proof of Continuity – A split function with a function to the power of a function – Exercise 6236 July 5, 2019 Proof of Continuity – A split function with ln and a third root – Exercise 6240 July 5, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Proof of Continuity – A split function with a polynomial and a rational function – Exercise 5871 June 30, 2019
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