Proof of Continuity – A split function with exponential functions with a parameter – Exercise 6248 Post category:Continuity by Definition Post comments:0 Comments Exercise Given the function f(x)={c+ex−e−xex+e−x,x<0ln(2−x),x≥0f(x) = \begin{cases} c+\frac{e^x-e^{-x}}{e^x+e^{-x}}, &\quad x<0\\ \ln(2-x), &\quad x\geq 0\\ \end{cases}f(x)={c+ex+e−xex−e−x,ln(2−x),x<0x≥0 c parameter. For what value of c is the function continuous at point x = 0? Final Answer Show final answer c=ln2c=\ln 2c=ln2 Solution Coming soon… Share with Friends Read more articles Previous PostProof of Continuity – A split function with exponential and rational functions – Exercise 6245 Next PostProof of Continuity – A split function with exponential functions – Exercise 6230 You Might Also Like Proof of Continuity – A split function with a rational function – Exercise 6223 July 5, 2019 Proof of Continuity – A split function with polynomials – Exercise 6243 July 5, 2019 Proof of Continuity – A split function with exponential functions and a parameter – Exercise 6591 July 16, 2019 Proof of Continuity – A split function with a function to the power of a function – Exercise 6236 July 5, 2019 Proof of Continuity – A split function with exponential functions – Exercise 6230 July 5, 2019 Proof of Continuity – A split function with first degree polynomial functions – Exercise 6220 July 5, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Proof of Continuity – A split function with exponential functions and a parameter – Exercise 6591 July 16, 2019
Proof of Continuity – A split function with a function to the power of a function – Exercise 6236 July 5, 2019
Proof of Continuity – A split function with first degree polynomial functions – Exercise 6220 July 5, 2019