Calculating Limit of Function – A quotient of polynomials to the power of a quotient of functions – Exercise 5939 Post category:Calculating Limit of Function Post comments:0 Comments Exercise Evaluate the following limit: limx→0(1+x2+x)1−x1−x\lim _ { x \rightarrow 0} {(\frac {1+x} {2+x})}^{\frac{1-\sqrt{x}}{1-x}}x→0lim(2+x1+x)1−x1−x Final Answer Show final answer limx→0(1+x2+x)1−x1−x=12\lim _ { x \rightarrow 0} {(\frac {1+x} {2+x})}^{\frac{1-\sqrt{x}}{1-x}}=\frac{1}{2}x→0lim(2+x1+x)1−x1−x=21 Solution Coming soon… Share with Friends Read more articles Previous PostCalculating Limit of Function – A quotient of functions with square and third roots – Exercise 5936 Next PostCalculating Limit of Function – A quotient of polynomials to the power of a quotient of functions – Exercise 5941 You Might Also Like Calculating Limit of Function – A quotient of polynomials in the power of a polynomial to infinity – Exercise 6559 July 15, 2019 Calculating Limit of Function – A rational function as x approaches infinity – Exercise 6169 July 4, 2019 Calculating Limit of Function – A multiplication of functions as x approaches infinity – Exercise 6042 July 3, 2019 Calculating Limit of Function – A quotient of polynomials – Exercise 5951 June 30, 2019 Calculating Limit of Function – A quotient of functions with a square root – Exercise 5925 June 30, 2019 Calculating Limit of Function – A difference of quotients – Exercise 5379 May 15, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
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