Calculating Limit of Function – A quotient of polynomials – Exercise 5911 Post category:Calculating Limit of Function Post comments:0 Comments Exercise Evaluate the following limit: limx→2(x2−x−2)20(x3−12x+16)10\lim _ { x \rightarrow 2} \frac {{(x^2-x - 2)}^{20}} {{(x^3-12x+16)}^{10}}x→2lim(x3−12x+16)10(x2−x−2)20 Final Answer Show final answer limx→2(x2−x−2)20(x3−12x+16)10=(32)10\lim _ { x \rightarrow 2} \frac {{(x^2-x - 2)}^{20}} {{(x^3-12x+16)}^{10}}={(\frac{3}{2})}^{10}x→2lim(x3−12x+16)10(x2−x−2)20=(23)10 Solution Coming soon… Share with Friends Read more articles Previous PostCalculating Limit of Function – A quotient of polynomials – Exercise 5908 Next PostCalculating Limit of Function – A quotient of polynomials – Exercise 5914 You Might Also Like Calculating Limit of Function – A quotient of functions with a square root – Exercise 5825 June 29, 2019 Calculating Limit of Function – A quotient of functions with a square root – Exercise 6202 July 4, 2019 Calculating Limit of Function – A quotient of functions with a square root – Exercise 5814 June 29, 2019 Calculating Limit of Function – A quotient of functions with square roots – Exercise 6217 July 4, 2019 Calculating Limit of Function – A difference of quotients – Exercise 5379 May 15, 2019 Calculating Limit of Function – A function with e in the power of a function to zero – Exercise 6319 July 6, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Calculating Limit of Function – A quotient of functions with a square root – Exercise 5825 June 29, 2019
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Calculating Limit of Function – A function with e in the power of a function to zero – Exercise 6319 July 6, 2019