Exercise
Solve the equation:
{(\sqrt{3})}^{3-x}=9^{x+2}
Final Answer
Solution
Using Powers and Roots rules we get:
{(\sqrt{3})}^{3-x}=9^{x+2}
3^{\frac{1}{2}(3-x)}=3^{2(x+2)}
\frac{1}{2}(3-x)=2(x+2)
3-x=4(x+2)
3-x=4x+8
-5x=5
x=-1
Solve the equation:
{(\sqrt{3})}^{3-x}=9^{x+2}
Final Answer
Using Powers and Roots rules we get:
{(\sqrt{3})}^{3-x}=9^{x+2}
3^{\frac{1}{2}(3-x)}=3^{2(x+2)}
\frac{1}{2}(3-x)=2(x+2)
3-x=4(x+2)
3-x=4x+8
-5x=5
x=-1