Logarithm Rules – Exercise 5574 Post category:Logarithms Post comments:0 Comments Exercise Solve the equation: logx(127)=3\log_x (\frac{1}{27})=3logx(271)=3 Final Answer Show final answer x=13x=\frac{1}{3}x=31 Solution Using Logarithm Rules we get: logx(127)=3\log_x (\frac{1}{27})=3logx(271)=3 −logx27=3-\log_x 27=3−logx27=3 −logx33=3-\log_x 3^3=3−logx33=3 −3logx3=3-3\log_x 3=3−3logx3=3 logx3=−1\log_x 3=-1logx3=−1 x−1=3x^{-1}=3x−1=3 1x=3\frac{1}{x}=3x1=3 x=13x=\frac{1}{3}x=31 Share with Friends Read more articles Previous PostLogarithm Rules – Exercise 941 Next PostLogarithm Rules – Exercise 5579 You Might Also Like Logarithm Rules – Exercise 5579 June 24, 2019 Logarithm Rules – Exercise 941 December 3, 2018 Logarithm Rules – Exercise 987 December 8, 2018 Logarithm Rules – Exercise 991 December 8, 2018 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ