Logarithm Rules – Exercise 5574

Exercise

Solve the equation:

logx(127)=3\log_x (\frac{1}{27})=3

Final Answer

x=13x=\frac{1}{3}

Solution

Using Logarithm Rules we get:

logx(127)=3\log_x (\frac{1}{27})=3

logx27=3-\log_x 27=3

logx33=3-\log_x 3^3=3

3logx3=3-3\log_x 3=3

logx3=1\log_x 3=-1

x1=3x^{-1}=3

1x=3\frac{1}{x}=3

x=13x=\frac{1}{3}

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