Exercise
Simplify the expression:
\frac{{(a^{-5} b^3)}^{-4}\cdot {(a^4)}^{-2}}{{(a^{-2})}^{-6}\cdot b^{-3}\cdot b^{-9}}
Final Answer
Solution
Using Powers and Roots rules we get:
\frac{{(a^{-5} b^3)}^{-4}\cdot {(a^4)}^{-2}}{{(a^{-2})}^{-6}\cdot b^{-3}\cdot b^{-9}}=
=\frac{a^{20}\cdot b^{-12}\cdot a^{-8}}{a^{12}\cdot b^{-12}}=
=\frac{a^{12}\cdot b^{-12}}{a^{12}\cdot b^{-12}}=
=1