Analytical Geometry – Calculate parameter values in a line equation – Exercise 5513 Post category:Analytical Geometry Post comments:0 Comments Exercise Calculate the values of parameters a and b given that x−4ba=y+ba−1=z−6a−2\frac{x-4b}{a}=\frac{y+b}{a-1}=\frac{z-6}{a-2}ax−4b=a−1y+b=a−2z−6 Is parallel to the plain x−2ay+z+10=0x-2ay+z+10=0x−2ay+z+10=0 And the distance between them is 6\sqrt{6}6 Final Answer Show final answer a=1a=1a=1 b=−53 or b=−113b=-\frac{5}{3} \text{ or } b=-\frac{11}{3}b=−35 or b=−311 Solution Coming soon… Share with Friends Read more articles Previous PostAnalytical Geometry – Calculate a point of intersection between a line and a plain – Exercise 5508 You Might Also Like Analytical Geometry – Calculate a point of intersection between a line and a plain – Exercise 5508 June 8, 2019 Analytical Geometry – Calculate a plane equation given a point and a perpendicular – Exercise 3599 February 27, 2019 Analytical Geometry – Calculate a plane equation with 3 points – Exercise 3603 February 27, 2019 Analytical Geometry – Calculate a plane equation with 3 points – Exercise 3610 February 27, 2019 Analytical Geometry – Calculate a plane equation with a point and a parallel plane – Exercise 3612 February 27, 2019 Analytical Geometry – Calculate the value of a parameter with perpendicular plains – Exercise 3614 February 27, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Analytical Geometry – Calculate a point of intersection between a line and a plain – Exercise 5508 June 8, 2019
Analytical Geometry – Calculate a plane equation given a point and a perpendicular – Exercise 3599 February 27, 2019
Analytical Geometry – Calculate a plane equation with a point and a parallel plane – Exercise 3612 February 27, 2019
Analytical Geometry – Calculate the value of a parameter with perpendicular plains – Exercise 3614 February 27, 2019