Extremum, Increase and Decrease Sections – Calculate absolute minimum and maximum in a closed interval – Exercise 5488

Exercise

Find the minimum and maximum points of the function

f(x)=x25e2xf(x)=\frac{x^2}{5e^{2x}}

In the interval

[12,2][-\frac{1}{2},2]

Final Answer


x=12,x=0x=-\frac{1}{2}, x=0

Solution

Coming soon…

Share with Friends

Leave a Reply