Improper Integral – A multiplication of a polynomial and exponential functions on an infinite interval – Exercise 5406

Exercise

Evaluate the integral

∫1∞xe−2xdx\int_1^{\infty} xe^{-2x} dx

Final Answer

∫1∞xe−2xdx=34e−2\int_1^{\infty} xe^{-2x} dx=\frac{3}{4}e^{-2}

Solution

Coming soon…

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