Spherical and Cylindrical Coordinates – On a cone – Exercise 4611 Post category:Spherical and Cylindrical Coordinates Post comments:0 Comments Exercise Calculate the integral ∫∫∫Tx2+y2dxdydz\int\int\int_T \sqrt{x^2+y^2} dxdydz∫∫∫Tx2+y2dxdydz Where T is bounded by the surfaces z=1,x2+y2=z2z=1, x^2+y^2=z^2z=1,x2+y2=z2 Final Answer Show final answer ∫∫∫Tx2+y2dxdydz=π6\int\int\int_T \sqrt{x^2+y^2} dxdydz=\frac{\pi}{6}∫∫∫Tx2+y2dxdydz=6π Solution Coming soon… Share with Friends Read more articles Previous PostSpherical and Cylindrical Coordinates – On a sphere – Exercise 4613 Next PostSpherical and Cylindrical Coordinates – On a sphere – Exercise 4606 You Might Also Like Spherical and Cylindrical Coordinates – On a sphere – Exercise 4606 April 15, 2019 Spherical and Cylindrical Coordinates – On a sphere – Exercise 4613 April 15, 2019 Spherical and Cylindrical Coordinates – On a cone – Exercise 4617 April 15, 2019 Spherical and Cylindrical Coordinates – On an ellipse – Exercise 4620 April 15, 2019 Spherical and Cylindrical Coordinates – Between a sphere and a cone – Exercise 4619 April 15, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ