Vectors – Calculate cosine direction of vector – Exercise 4508 Post category:Vectors Post comments:0 Comments Exercise Calculate the cosine direction of the vector a⃗=2i⃗−2j⃗+k⃗\vec{a}=2\vec{i}-2\vec{j}+\vec{k}a=2i−2j+k Final Answer Show final answer cosα=23\cos\alpha=\frac{2}{3}cosα=32 cosβ=−23\cos\beta=\frac{-2}{3}cosβ=3−2 cosγ=13\cos\gamma=\frac{1}{3}cosγ=31 Solution Coming soon… Share with Friends Read more articles Previous PostVectors – Calculate cosine direction of vector with x-axis – Exercise 4512 Next PostVectors – Proof that four given points form a square – Exercise 4489 You Might Also Like Vectors – Calculate the scalar multiplication of vectors – Exercise 3564 February 26, 2019 Vectors – Prove an equation of vectors – Exercise 3573 February 26, 2019 Vectors – Proof that the rhombus diagonals are perpendicular – Exercise 3576 February 26, 2019 Vectors – Calculate angle between two vectors – Exercise 3581 February 27, 2019 Vectors – Calculation of scalar multiplication between vectors in vector presentation – Exercise 3584 February 27, 2019 Vectors – Calculate angle between two vectors in vector representation – Exercise 3586 February 27, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Vectors – Calculation of scalar multiplication between vectors in vector presentation – Exercise 3584 February 27, 2019
Vectors – Calculate angle between two vectors in vector representation – Exercise 3586 February 27, 2019
