Vectors – Calculate the length of diagonals of a parallelogram – Exercise 4469 Post category:Vectors Post comments:0 Comments Exercise Calculate the lengths of the parallelogram diagonasl built on the vectors a⃗=5p⃗+2q⃗\vec{a}=5\vec{p}+2\vec{q}a=5p+2q b⃗=p⃗−3q⃗\vec{b}=\vec{p}-3\vec{q}b=p−3q Given that ∣p⃗∣=22,∣q⃗∣=3|\vec{p}|=2\sqrt{2}, |\vec{q}|=3∣p∣=22,∣q∣=3 And the angle between them is equal to 45 degrees. Final Answer Show final answer ∣a⃗+b⃗∣=15|\vec{a}+\vec{b}|=15∣a+b∣=15 ∣b⃗−a⃗∣=593|\vec{b}-\vec{a}|=\sqrt{593}∣b−a∣=593 Solution Coming soon… Share with Friends Read more articles Previous PostVectors – Calculate angles of a triangle – Exercise 4471 Next PostVectors – collinear calculation – Exercise 3597 You Might Also Like Vectors – Calculate the scalar multiplication of vectors – Exercise 3564 February 26, 2019 Vectors – Prove an equation of vectors – Exercise 3573 February 26, 2019 Vectors – Proof that the rhombus diagonals are perpendicular – Exercise 3576 February 26, 2019 Vectors – Calculate angle between two vectors – Exercise 3581 February 27, 2019 Vectors – Calculation of scalar multiplication between vectors in vector presentation – Exercise 3584 February 27, 2019 Vectors – Calculate angle between two vectors in vector representation – Exercise 3586 February 27, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Vectors – Calculation of scalar multiplication between vectors in vector presentation – Exercise 3584 February 27, 2019
Vectors – Calculate angle between two vectors in vector representation – Exercise 3586 February 27, 2019