Vectors – Calculate the length of diagonals of a parallelogram – Exercise 4469

Exercise

Calculate the lengths of the parallelogram diagonasl built on the vectors

a=5p+2q\vec{a}=5\vec{p}+2\vec{q}

b=p3q\vec{b}=\vec{p}-3\vec{q}

Given that

p=22,q=3|\vec{p}|=2\sqrt{2}, |\vec{q}|=3

And the angle between them is equal to 45 degrees.

Final Answer

a+b=15|\vec{a}+\vec{b}|=15

ba=593|\vec{b}-\vec{a}|=\sqrt{593}

Solution

Coming soon…

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