Exercise
Find second order partial derivatives of the function
u(x,y,z)=2x^3y+x^2z^3
Final Answer
u''_{xx} (x,y,z)=12yx+2z^3
u''_{yy} (x,y,z)=0
u''_{zz} (x,y,z)=6x^2z
u''_{xy} (x,y,z)=u''_{yx} (x,y,z)=6x^2
u''_{yz} (x,y,z)=u''_{zy} (x,y,z)=0
u''_{xz} (x,y,z)=u''_{zx} (x,y,z)=6xz^2
Solution
Coming soon…