Exercise
Find second order partial derivatives of the function
z(x,y)=\sqrt{x^2+y^2}
Final Answer
z''_{xx} (x,y)=\frac{y^2}{{(x^2+y^2)}^{\frac{3}{2}}}
z''_{yy} (x,y)=\frac{x^2}{{(x^2+y^2)}^{\frac{3}{2}}}
z''_{xy} (x,y)=z''_{yx}(x,y)=\frac{-xy}{{(x^2+y^2)}^{\frac{3}{2}}}
Solution
Coming soon…