Directional Derivative – Proof that the directional derivative is equal to a certain value – Exercise 4292 Post category:Directional Derivative Post comments:0 Comments Exercise Prove that the directional derivative of the function u=x2a2+y2b2+z2c2u=\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}u=a2x2+b2y2+c2z2 At any point (x, y, z) and in the direction from the point to the origin is equal to −2ur\frac{-2u}{r}r−2u Where r=x2+y2+z2r=\sqrt{x^2+y^2+z^2}r=x2+y2+z2 Proof Coming soon… Share with Friends Read more articles Previous PostDirectional Derivative – Calculate maximum value – Exercise 4295 Next PostDirectional Derivative – Calculating Derivative oriented by an angle – Exercise 4290 You Might Also Like Directional Derivative – Calculating Derivative – Exercise 4279 March 24, 2019 Directional Derivative – Calculating Derivative – Exercise 4285 March 24, 2019 Directional Derivative – Calculating Derivative oriented by an angle – Exercise 4290 March 24, 2019 Directional Derivative – Calculate maximum value – Exercise 4295 March 24, 2019 Directional Derivative – Calculating Derivative oriented by angles – Exercise 4299 March 25, 2019 Directional Derivative – Calculate maximum value and minimum value – Exercise 4302 March 25, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ