Gradient – Calculate maximum direction – Exercise 4265 Post category:Gradient Post comments:0 Comments Exercise Calculate the direction in which the rate of differentiation of the scalar field u=\ln(x^2+y^2+z^2) At point (1,2,1) it is maximal. Final Answer Show final answer \hat{\nabla} u(1,2,1)=\frac{1}{\sqrt{6}}\vec{i}+\frac{2}{\sqrt{6}}\vec{j}+\frac{1}{\sqrt{6}}\vec{k} Solution Coming soon… Share with Friends Read more articles Previous PostGradient – Calculate points where a particular gradient is obtained – Exercise 4275 Next PostGradient – A scalar field of x multiplied by an exponential function – Exercise 4262 You Might Also Like Gradient – A scalar field with ln and a square root – Exercise 4254 March 24, 2019 Gradient – Calculate scalar field gradient and direction – Exercise 4257 March 24, 2019 Gradient – A scalar field of x multiplied by an exponential function – Exercise 4262 March 24, 2019 Gradient – Calculate points where a particular gradient is obtained – Exercise 4275 March 24, 2019 Gradient – Tangent Plane Equation – Exercise 4361 March 26, 2019 Gradient – Tangent Plane Equation – Exercise 4363 March 26, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ