Gradient – A scalar field with ln and a square root – Exercise 4254 Post category:Gradient Post comments:0 Comments Exercise Calculate the gradient of the scalar field u=lnx2+y2+z2u=\ln\sqrt{x^2+y^2+z^2}u=lnx2+y2+z2 At point (1,1,1). Final Answer Show final answer ∇u(1,1,1)=(13,13,13)\nabla u(1,1,1)=(\frac{1}{3},\frac{1}{3},\frac{1}{3})∇u(1,1,1)=(31,31,31) Solution Coming soon… Share with Friends Read more articles Previous PostGradient – Calculate scalar field gradient and direction – Exercise 4257 You Might Also Like Gradient – Calculate scalar field gradient and direction – Exercise 4257 March 24, 2019 Gradient – A scalar field of x multiplied by an exponential function – Exercise 4262 March 24, 2019 Gradient – Calculate maximum direction – Exercise 4265 March 24, 2019 Gradient – Calculate points where a particular gradient is obtained – Exercise 4275 March 24, 2019 Gradient – Tangent Plane Equation – Exercise 4361 March 26, 2019 Gradient – Tangent Plane Equation – Exercise 4363 March 26, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
