We will find the function differential with the differential formula
dg=gx′dx+gy′dy+gz′dz
In the formula above we see the function partial derivatives. Hence, we calculate them.
gx′(x,y,z)=2xy4+y2−6xz
gy′(x,y,z)=4y3x2+2xy+z2
gz′(x,y,z)=−3x2+2zy
Now, we put the derivatives in the formula and get
dg=gx′dx+gy′dy+gz′dz
du=(2xy4+y2−6xz)dx+(4y3x2+2xy+z2)dy+(−3x2+2zy)dz
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