Calculating Differential – Exercise 4242

Exercise

Find the differential of the function

g=x2y4+xy23x2z+z2yg=x^2y^4+xy^2-3x^2z+z^2y

Final Answer


du=(2xy4+y26xz)dx+(4y3x2+2xy+z2)dy+(3x2+2zy)dzdu=(2xy^4+y^2-6xz)dx+(4y^3x^2+2xy+z^2)dy+(-3x^2+2zy)dz

Solution

We will find the function differential with the differential formula

dg=gxdx+gydy+gzdzdg=g'_x dx+g'_y dy+g'_z dz

In the formula above we see the function partial derivatives. Hence, we calculate them.

gx(x,y,z)=2xy4+y26xzg'_x(x,y,z)=2xy^4+y^2-6xz

gy(x,y,z)=4y3x2+2xy+z2g'_y(x,y,z)=4y^3x^2+2xy+z^2

gz(x,y,z)=3x2+2zyg'_z(x,y,z)=-3x^2+2zy

Now, we put the derivatives in the formula and get

dg=gxdx+gydy+gzdzdg=g'_x dx+g'_y dy+g'_z dz

du=(2xy4+y26xz)dx+(4y3x2+2xy+z2)dy+(3x2+2zy)dzdu=(2xy^4+y^2-6xz)dx+(4y^3x^2+2xy+z^2)dy+(-3x^2+2zy)dz

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