Continuity of Multivariable functions – A quotient of functions with sin – Exercise 4195 Post category:Continuity of Multivariable Functions Post comments:0 Comments Exercise Is the function f(x,y)={(x−1)(y−2)(x−1)2+sin2(y−2),(x,y)≠(1,2)0,(x,y)=(1,2)f(x,y) = \begin{cases} \frac{(x-1)(y-2)}{{(x-1)}^2+\sin^2(y-2)}, &\quad (x,y) \not= (1,2)\\ 0, &\quad (x,y)= (1,2)\\ \end{cases}f(x,y)={(x−1)2+sin2(y−2)(x−1)(y−2),0,(x,y)=(1,2)(x,y)=(1,2) Continuous at point (1,2)? Final Answer Show final answer No Solution Coming soon… Share with Friends Read more articles Previous PostContinuity of Multivariable functions – A quotient of functions with sin – Exercise 4204 Next PostContinuity of Multivariable functions – A quotient of functions – Exercise 4191 You Might Also Like Continuity of Multivariable functions – A quotient of functions – Exercise 4191 March 22, 2019 Continuity of Multivariable functions – A quotient of functions with sin – Exercise 4204 March 22, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Continuity of Multivariable functions – A quotient of functions with sin – Exercise 4204 March 22, 2019