Surface Integrals – On a plane – Exercise 4109 Post category:Surface Integrals Post comments:0 Comments Exercise Calculate the integral ∫∫SPdydz+Qdxdz+Rdxdy\int\int_S Pdydz + Qdxdz +Rdxdy∫∫SPdydz+Qdxdz+Rdxdy Where P=y−x,Q=x+y,R=yP=y-x, Q=x+y, R=yP=y−x,Q=x+y,R=y And the surface S is the outer side of the plane x+y+z=1,x≥0,y≥0,z≥0x+y+z=1, x\geq 0, y\geq 0, z\geq 0x+y+z=1,x≥0,y≥0,z≥0 Final Answer Show final answer ∫∫SF⃗n^ds=12\int\int_S \vec{F}\hat{n}ds=\frac{1}{2}∫∫SFn^ds=21 Solution Coming soon… Share with Friends Read more articles Previous PostSurface Integrals – On a cone – Exercise 4120 Next PostSurface Integrals – On a cone – Exercise 4103 You Might Also Like Surface Integrals – On a closed domain – Exercise 4782 May 8, 2019 Surface Integrals – On a hemisphere – Exercise 4089 March 17, 2019 Surface Integrals – On a cone – Exercise 4103 March 17, 2019 Surface Integrals – On a cone – Exercise 4120 March 19, 2019 Surface Integrals – On a cylinder – Exercise 4048 March 15, 2019 Surface Integrals – On a paraboloid – Exercise 4055 March 15, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ