Surface Integrals – Surface area of a plane – Exercise 4074 Post category:Surface Integrals Post comments:0 Comments Exercise Calculate the surface area of the plane x+2y+3z=6 That is between the planes x=0,y=0,z=0 Final Answer Show final answer \int\int_S ds=3\sqrt{14} Solution Coming soon… Share with Friends Read more articles Previous PostSurface Integrals – Surface area of a paraboloid – Exercise 4078 Next PostSurface Integrals – On a cone – Exercise 4068 You Might Also Like Surface Integrals – On a closed domain – Exercise 4782 May 8, 2019 Surface Integrals – On a hemisphere – Exercise 4089 March 17, 2019 Surface Integrals – On a cone – Exercise 4103 March 17, 2019 Surface Integrals – On a plane – Exercise 4109 March 17, 2019 Surface Integrals – On a cone – Exercise 4120 March 19, 2019 Surface Integrals – On a cylinder – Exercise 4048 March 15, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ