Surface Integrals – On a paraboloid – Exercise 4055 Post category:Surface Integrals Post comments:0 Comments Exercise Calculate the integral ∫∫S3zds\int\int_S 3zds∫∫S3zds Where S is S={z=2−x2−y2,z≥0}S=\{z=2-x^2-y^2,z\geq 0 \}S={z=2−x2−y2,z≥0} Final Answer Show final answer ∫∫S3zds=11.1π\int\int_S 3zds=11.1\pi∫∫S3zds=11.1π Solution Coming soon… Share with Friends Read more articles Previous PostSurface Integrals – On a cone – Exercise 4068 Next PostSurface Integrals – On a cylinder – Exercise 4048 You Might Also Like Surface Integrals – On a closed domain – Exercise 4782 May 8, 2019 Surface Integrals – On a hemisphere – Exercise 4089 March 17, 2019 Surface Integrals – On a cone – Exercise 4103 March 17, 2019 Surface Integrals – On a plane – Exercise 4109 March 17, 2019 Surface Integrals – On a cone – Exercise 4120 March 19, 2019 Surface Integrals – On a cylinder – Exercise 4048 March 15, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
