Surface Integrals – On a cylinder – Exercise 4048 Post category:Surface Integrals Post comments:0 Comments Exercise Calculate the integral ∫∫Sz(x+y)ds\int\int_S z(x+y)ds∫∫Sz(x+y)ds Where S is S={z=4−x2,0≤y≤5}S=\{z=\sqrt{4-x^2},0\leq y\leq 5 \}S={z=4−x2,0≤y≤5} Final Answer Show final answer ∫∫Sz(x+y)ds=100\int\int_S z(x+y)ds=100∫∫Sz(x+y)ds=100 Solution Coming soon… Share with Friends Read more articles Previous PostSurface Integrals – On a paraboloid – Exercise 4055 Next PostSurface Integrals – On a cone – Exercise 4120 You Might Also Like Surface Integrals – On a closed domain – Exercise 4782 May 8, 2019 Surface Integrals – On a hemisphere – Exercise 4089 March 17, 2019 Surface Integrals – On a cone – Exercise 4103 March 17, 2019 Surface Integrals – On a plane – Exercise 4109 March 17, 2019 Surface Integrals – On a cone – Exercise 4120 March 19, 2019 Surface Integrals – On a paraboloid – Exercise 4055 March 15, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
