Polar Coordinates – Fixed integration limits – Exercise 3976 Post category:Polar Coordinates Post comments:0 Comments Exercise Calculate the double integral ∫02πdθ∫0ar2sin2θdr\int_0^{2\pi}d\theta\int_0^a r^2\sin^2\theta dr∫02πdθ∫0ar2sin2θdr Final Answer Show final answer ∫02πdθ∫0ar2sin2θdr=a3π3\int_0^{2\pi}d\theta\int_0^a r^2\sin^2\theta dr=\frac{a^3\pi}{3}∫02πdθ∫0ar2sin2θdr=3a3π Solution Coming soon… Share with Friends Read more articles Previous PostPolar Coordinates – Finding integration limits in polar coordinates – Exercise 3980 You Might Also Like Polar Coordinates – Finding integration limits in polar coordinates – Exercise 3980 March 10, 2019 Polar Coordinates – Finding integration limits in polar coordinates – Exercise 3986 March 10, 2019 Polar Coordinates – Finding integration limits in polar coordinates – Exercise 3992 March 10, 2019 Polar Coordinates – Finding integration limits in polar coordinates – Exercise 3994 March 10, 2019 Polar Coordinates – Finding integration limits in polar coordinates – Exercise 3997 March 10, 2019 Polar Coordinates – Finding integration limits in polar coordinates – Exercise 4002 March 10, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
