Vector uses in physics – Calculate motion – Exercise 3874

Exercise

Particle acceleration depends on time according to the acceleration formula

a(t)=18cos(3t)i18sin(3t)j\vec{a}(t)=18\cos(3t)\vec{i}-18\sin(3t)\vec{j}

The initial vector radius of the particle is

r(0)=(2,0,1)\vec{r}(0)=(2,0,1)

And the initial velocity of the particle is

v(0)=(0,2,4)\vec{v}(0)=(0,2,4)

Calculate the equation of motion of the particle.

Final Answer

r(t)=(2cos(3t)+4)i+(2sin(3t)4t)j+(4t+1)k\vec{r}(t)=(-2\cos(3t)+4)\vec{i}+(2\sin(3t)-4t)\vec{j}+(4t+1)\vec{k}

Solution

Coming soon…

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