Vector Derivative and Tangent – Calculate a unit tangent vector to a curve in a vector presentation – Exercise 3846 Post category:Vector Derivative and Tangent Post comments:0 Comments Exercise Calculate a unit tangent vector to the curve: r⃗(t)=2ln(t+1)i⃗+t2j⃗+12t2k⃗\vec{r}(t)=2\ln(t+1)\vec{i}+t^2\vec{j}+\frac{1}{2}t^2\vec{k}r(t)=2ln(t+1)i+t2j+21t2k At a point corresponding to t = 1. Final Answer Show final answer p^=(16,26,16)\hat{p}=(\frac{1}{\sqrt{6}},\frac{2}{\sqrt{6}},\frac{1}{\sqrt{6}})p^=(61,62,61) Solution Coming soon… Share with Friends Read more articles Next PostVector Derivative and Tangent – Unit tangent vector to a curve in a vector presentation – Exercise 3842 You Might Also Like Vector Derivative and Tangent – Calculating Derivative and a derivative size of a vector function – Exercise 3820 March 3, 2019 Vector Derivative and Tangent – Calculating derivative of a vector function – Exercise 3825 March 3, 2019 Vector Derivative and Tangent – A tangent calculation for a curve in a vector presentation – Exercise 3828 March 3, 2019 Vector Derivative and Tangent – A tangent calculation for a curve in a vector presentation – Exercise 3833 March 4, 2019 Vector Derivative and Tangent – A tangent calculation for a curve in a vector presentation – Exercise 3836 March 4, 2019 Vector Derivative and Tangent – Tangent to the curve in a vector representation parallel to a given plane – Exercise 3839 March 4, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Vector Derivative and Tangent – Calculating Derivative and a derivative size of a vector function – Exercise 3820 March 3, 2019
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