Vector Derivative and Tangent – Tangent to the curve in a vector representation parallel to a given plane – Exercise 3839 Post category:Vector Derivative and Tangent Post comments:0 Comments Exercise Find a point on the curve r⃗(t)=t2i⃗+tj⃗+5k⃗\vec{r}(t)=t^2\vec{i}+t\vec{j}+5\vec{k}r(t)=t2i+tj+5k Where the tangent to a curve is parallel to the plain x−6y+4z=3x-6y+4z=3x−6y+4z=3 Final Answer Show final answer M(9,3,5)M(9,3,5)M(9,3,5) Solution Coming soon… Share with Friends Read more articles Previous PostVector Derivative and Tangent – Unit tangent vector to a curve in a vector presentation – Exercise 3842 Next PostVector Derivative and Tangent – A tangent calculation for a curve in a vector presentation – Exercise 3836 You Might Also Like Vector Derivative and Tangent – Calculating Derivative and a derivative size of a vector function – Exercise 3820 March 3, 2019 Vector Derivative and Tangent – Calculating derivative of a vector function – Exercise 3825 March 3, 2019 Vector Derivative and Tangent – A tangent calculation for a curve in a vector presentation – Exercise 3828 March 3, 2019 Vector Derivative and Tangent – A tangent calculation for a curve in a vector presentation – Exercise 3833 March 4, 2019 Vector Derivative and Tangent – A tangent calculation for a curve in a vector presentation – Exercise 3836 March 4, 2019 Vector Derivative and Tangent – Unit tangent vector to a curve in a vector presentation – Exercise 3842 March 4, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Vector Derivative and Tangent – Calculating Derivative and a derivative size of a vector function – Exercise 3820 March 3, 2019
Vector Derivative and Tangent – Calculating derivative of a vector function – Exercise 3825 March 3, 2019
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Vector Derivative and Tangent – A tangent calculation for a curve in a vector presentation – Exercise 3833 March 4, 2019
Vector Derivative and Tangent – A tangent calculation for a curve in a vector presentation – Exercise 3836 March 4, 2019
Vector Derivative and Tangent – Unit tangent vector to a curve in a vector presentation – Exercise 3842 March 4, 2019