Different Representation of Curves – Switch from Cartesian to vector – Exercise 3809 Post category:Different Representations of Curves Post comments:0 Comments Exercise A curve is given as an intersection of the surfaces x^2=z y^2=x Present the curve in the vector presentation. Final Answer Show final answer \vec{r}(t)=t^2\vec{i}+t\vec{j}+t^4\vec{k} Solution Coming soon… Share with Friends Read more articles Next PostDifferent Representation of Curves – Switch from Cartesian to vector – Exercise 3807 You Might Also Like Different Representation of Curves – Switch from parametric to Cartesian – Exercise 3704 March 2, 2019 Different Representation of Curves – Switch from parametric to Cartesian – Exercise 3722 March 2, 2019 Different Representation of Curves – Switch from parametric to Cartesian – Exercise 3707 March 2, 2019 Different Representation of Curves – Switch from parametric to Cartesian – Exercise 3715 March 2, 2019 Different Representation of Curves – Switch from parametric to Cartesian – Exercise 3732 March 2, 2019 הDifferent Representation of Curves – Switch from parametric to Cartesian – Exercise 3742 March 2, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Different Representation of Curves – Switch from parametric to Cartesian – Exercise 3704 March 2, 2019
Different Representation of Curves – Switch from parametric to Cartesian – Exercise 3722 March 2, 2019
Different Representation of Curves – Switch from parametric to Cartesian – Exercise 3707 March 2, 2019
Different Representation of Curves – Switch from parametric to Cartesian – Exercise 3715 March 2, 2019
Different Representation of Curves – Switch from parametric to Cartesian – Exercise 3732 March 2, 2019
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