Different Representation of Curves – Switch from Cartesian to vector – Exercise 3793

Exercise

Given the curve

x+y=1\sqrt{x}+\sqrt{y}=1

Where

x0,y0x\geq 0,y\geq 0

Present the curve in the vector presentation.

Final Answer

r(t)=t2i+(1t)2j\vec{r}(t)=t^2\vec{i}+{(1-t)}^2\vec{j}

Solution

Coming soon…

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