Global Extremum – Domain of a curve with absolute value – Exercise 3471 Post category:Global Extremum Post comments:0 Comments Exercise Find the maximum value and the minimum value of the function z(x,y)=x2−xy+y2z(x,y)=x^2-xy+y^2z(x,y)=x2−xy+y2 In the domain D={(x,y):∣x∣+∣y∣≤1}D=\{ (x,y): |x|+|y|\leq 1\}D={(x,y):∣x∣+∣y∣≤1} Final Answer Show final answer maxDz(0,±1)=maxDz(±1,0)=1\max_D z(0,\pm 1)=\max_D z(\pm 1,0) =1Dmaxz(0,±1)=Dmaxz(±1,0)=1 minDz(0,0)=0\min_D z(0,0) =0Dminz(0,0)=0 Solution Coming soon… Share with Friends Read more articles Previous PostGlobal Extremum – Domain of a circle – Exercise 3479 Next PostGlobal Extremum – Domain of a parabola and a line – Exercise 3463 You Might Also Like Global Extremum – Domain of a circle – Exercise 6538 July 15, 2019 Global Extremum – Domain of lines – Exercise 5529 June 9, 2019 Global Extremum – Domain of a circle – Exercise 6543 July 15, 2019 Global Extremum – Domain of ellipse – Exercise 5392 May 15, 2019 Global Extremum – Domain of ellipse – Exercise 4749 May 6, 2019 Global Extremum – Domain of a function with fixed negative powers – Exercise 6551 July 23, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
