Calculating Limit of Function – A quotient of functions with sin, cos and tan – Exercise 314 Post category:Calculating Limit of Function Post comments:0 Comments Exercise Evaluate the following limit: \lim _ { x \rightarrow 0 } \frac {5 x + \sin ( 3 x )} {\tan ( 4 x ) - 7 x \cos ( 2 x )} Final Answer Show final answer \lim _ { x \rightarrow 0 } \frac {5 x + \sin ( 3 x )} {\tan ( 4 x ) - 7 x \cos ( 2 x )} = -\frac {8}{3} Solution Coming soon… Share with Friends Read more articles Previous PostCalculating Limit of Function – A quotient of functions with sin – Exercise 329 Next PostCalculating Limit of Function – A quotient of functions with cos – Exercise 295 You Might Also Like Calculating Limit of Function – A quotient of functions to infinity – Exercise 6579 July 15, 2019 Calculating Limit of Function – A quotient of functions with square roots – Exercise 5827 June 29, 2019 Calculating Limit of Function – A rational function – Exercise 5793 June 29, 2019 Calculating Limit of Function – One-sided limit to a quotient of functions as x approaches zero – Exercise 6048 July 4, 2019 Calculating Limit of Function – A quotient of polynomials to the power of a quotient – Exercise 5996 July 2, 2019 Calculating Limit of Function – A quotient of functions with a square root – Exercise 6199 July 4, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Calculating Limit of Function – A quotient of functions with square roots – Exercise 5827 June 29, 2019
Calculating Limit of Function – One-sided limit to a quotient of functions as x approaches zero – Exercise 6048 July 4, 2019
Calculating Limit of Function – A quotient of polynomials to the power of a quotient – Exercise 5996 July 2, 2019
Calculating Limit of Function – A quotient of functions with a square root – Exercise 6199 July 4, 2019