Calculating Limit of Function – A quotient of functions with sin, cos and tan – Exercise 314 Post category:Calculating Limit of Function Post comments:0 Comments Exercise Evaluate the following limit: limx→05x+sin(3x)tan(4x)−7xcos(2x)\lim _ { x \rightarrow 0 } \frac {5 x + \sin ( 3 x )} {\tan ( 4 x ) - 7 x \cos ( 2 x )}x→0limtan(4x)−7xcos(2x)5x+sin(3x) Final Answer Show final answer limx→05x+sin(3x)tan(4x)−7xcos(2x)=−83\lim _ { x \rightarrow 0 } \frac {5 x + \sin ( 3 x )} {\tan ( 4 x ) - 7 x \cos ( 2 x )} = -\frac {8}{3}x→0limtan(4x)−7xcos(2x)5x+sin(3x)=−38 Solution Coming soon… Share with Friends Read more articles Previous PostCalculating Limit of Function – A quotient of functions with sin – Exercise 329 Next PostCalculating Limit of Function – A quotient of functions with cos – Exercise 295 You Might Also Like Calculating Limit of Function – A quotient of polynomials in the power of a polynomial to infinity – Exercise 6559 July 15, 2019 Calculating Limit of Function – A function with e in the power of a function with e to infinity – Exercise 6329 July 6, 2019 Calculating Limit of Function – One-sided limit on a rational function – Exercise 6178 July 4, 2019 Calculating Limit of Function – A quotient of polynomials to the power of a polynomial – Exercise 6015 July 3, 2019 Calculating Limit of Function – A ln function divided by x – Exercise 5965 July 2, 2019 Calculating Limit of Function- A function with ln in the power of x to 0 from right – Exercise 6323 July 6, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
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