Calculating Limit of Function – A quotient of functions with cos – Exercise 268 Post category:Calculating Limit of Function Post comments:0 Comments Exercise Evaluate the following limit: limx→0cos(2x)−1cosx−1\lim _ { x \rightarrow 0 } \frac {\cos ( 2 x ) - 1} {\cos x - 1}x→0limcosx−1cos(2x)−1 Final Answer Show final answer limx→0cos(2x)−1cosx−1=4\lim _ { x \rightarrow 0 } \frac {\cos ( 2 x ) - 1} {\cos x - 1} = 4x→0limcosx−1cos(2x)−1=4 Solution Coming soon… Share with Friends Read more articles Previous PostCalculating Limit of Function – A quotient of functions with cos – Exercise 295 Next PostCalculating Limit of Function – A quotient of functions – Exercise 250 You Might Also Like Calculating Limit of Function – A quotient of polynomials of the same degree – Exercise 5902 June 30, 2019 Calculating Limit of Function – A quotient of polynomials – Exercise 5896 June 30, 2019 Calculating Limit of Function – A rational function – Exercise 5956 June 30, 2019 Calculating Limit of Function – A quotient of functions with square roots – Exercise 5790 June 29, 2019 Calculating Limit of Function- A function with ln in the power of x to 0 from right – Exercise 6323 July 6, 2019 Calculating Limit of Function – ln function multiplies by ln function to infinity – Exercise 6587 July 15, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Calculating Limit of Function – A quotient of polynomials of the same degree – Exercise 5902 June 30, 2019
Calculating Limit of Function – A quotient of functions with square roots – Exercise 5790 June 29, 2019
Calculating Limit of Function- A function with ln in the power of x to 0 from right – Exercise 6323 July 6, 2019
Calculating Limit of Function – ln function multiplies by ln function to infinity – Exercise 6587 July 15, 2019
