Fundamental Theorem of Calculus – Exercise 2358 Post category:Fundamental Theorem of Calculus Post comments:0 Comments Exercise Find the derivative of the following function g(x)=\int_2^{\sin x} \sqrt[3]{t} dt Final Answer Show final answer g'(x)=\sqrt[3]{\sin x}\cdot \cos x Solution Coming soon… Share with Friends Read more articles Previous PostFundamental Theorem of Calculus – Exercise 2367 You Might Also Like Fundamental Theorem of Calculus – Exercise 2367 January 6, 2019 Fundamental Theorem of Calculus – Exercise 2370 January 6, 2019 Fundamental Theorem of Calculus – Exercise 2372 January 6, 2019 Fundamental Theorem of Calculus – Exercise 2376 January 6, 2019 Fundamental Theorem of Calculus – Exercise 2382 January 14, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ