Riemann Sum – Exercise 2311 Post category:Riemann Sum Post comments:0 Comments Exercise Evaluate the limit limn→∞∑k=1n(12n+8kn2)\lim_{n \rightarrow \infty}\sum_{k=1}^n (\frac{12}{n}+\frac{8k}{n^2})n→∞limk=1∑n(n12+n28k) Final Answer Show final answer limn→∞∑k=1n(12n+8kn2)=16\lim_{n \rightarrow \infty}\sum_{k=1}^n (\frac{12}{n}+\frac{8k}{n^2})=16n→∞limk=1∑n(n12+n28k)=16 Solution Coming soon… Share with Friends Read more articles Previous PostRiemann Sum – Exercise 2318 You Might Also Like Riemann Sum – Exercise 2318 January 6, 2019 Riemann Sum – Exercise 2322 January 6, 2019 Riemann Sum – Exercise 2330 January 6, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
