Extremum, Increase and Decrease Sections – Calculate global Extremum Points – Exercise 2225 Post category:Extremum, Increase and Decrease Sections Post comments:0 Comments Exercise Find global extremum points to the function f(x)=xe−x2f(x)=xe^{-x^2}f(x)=xe−x2 In the interval (−∞,∞)(-\infty, \infty)(−∞,∞) Final Answer Show final answer (12,12e),(−12,−12e)(\sqrt{\frac{1}{2}},\frac{1}{\sqrt{2e}}),(-\sqrt{\frac{1}{2}},\frac{-1}{\sqrt{2e}})(21,2e1),(−21,2e−1) Solution Coming soon… Share with Friends Read more articles Previous PostExtremum, Increase and Decrease Sections – Min and max problem (closest point to the graph) – Exercise 2136 Next PostExtremum, Increase and Decrease Sections – Proof of inequality – Exercise 2222 You Might Also Like Extremum, Increase and Decrease Sections – x multiplied by an exponential function – Exercise 6831 July 25, 2019 Extremum, Increase and Decrease sections – Extremum to a polynomial function in a closed interval – Exercise 6913 July 30, 2019 Extremum, Increase and Decrease sections – Extremum to a polynomial function inside a square root in a closed interval – Exercise 6916 July 30, 2019 Extremum, Increase and Decrease Sections – A rational function – Exercise 6820 July 24, 2019 Extremum, Increase and Decrease Sections – Calculate absolute minimum and maximum in a closed interval – Exercise 5488 May 25, 2019 Extremum, Increase and Decrease Sections – A polynomial – Exercise 6805 July 24, 2019 Leave a Reply Cancel replyCommentEnter your name or username to comment Enter your email address to comment Enter your website URL (optional) Δ
Extremum, Increase and Decrease Sections – x multiplied by an exponential function – Exercise 6831 July 25, 2019
Extremum, Increase and Decrease sections – Extremum to a polynomial function in a closed interval – Exercise 6913 July 30, 2019
Extremum, Increase and Decrease sections – Extremum to a polynomial function inside a square root in a closed interval – Exercise 6916 July 30, 2019
Extremum, Increase and Decrease Sections – Calculate absolute minimum and maximum in a closed interval – Exercise 5488 May 25, 2019